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9b^2+21b+10=0
a = 9; b = 21; c = +10;
Δ = b2-4ac
Δ = 212-4·9·10
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-9}{2*9}=\frac{-30}{18} =-1+2/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+9}{2*9}=\frac{-12}{18} =-2/3 $
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